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Simple Interest questions

Interest, amount, rate and time.

1. The simple interest on ₹17,000 for 4 years is ₹4,080. What is the rate of interest?

  1. 6% p.a.
  2. 7% p.a.
  3. 9% p.a.
  4. 5% p.a.
Answer

A. 6% p.a. R = SI × 100 / (P × T) = 4080 × 100 / (17000 × 4) = 6%.

2. A sum amounts to ₹19,040 in 3 years at 12% simple interest per annum. What is the sum?

  1. ₹10,500
  2. ₹13,999
  3. ₹14,001
  4. ₹14,000
Answer

D. ₹14,000 Amount = P(1 + 36/100), so P = 19040 ÷ 1.3599999999999999 = ₹14,000.

3. At what time will a sum double itself at 5% simple interest per annum?

  1. 40 years
  2. 20 years
  3. 18 years
  4. 22 years
Answer

B. 20 years Doubling means SI = P. P × 5 × T / 100 = P, so T = 100/5 = 20 years.

4. Find the simple interest on ₹25,000 at 8% per annum for 3 years.

  1. ₹6,000
  2. ₹6,600
  3. ₹6,001
  4. ₹7,200
Answer

A. ₹6,000 SI = P × R × T / 100 = 25000 × 8 × 3 / 100 = ₹6,000.

5. The simple interest on ₹20,000 for 5 years is ₹10,000. What is the rate of interest?

  1. 13% p.a.
  2. 10% p.a.
  3. 20% p.a.
  4. 12% p.a.
Answer

B. 10% p.a. R = SI × 100 / (P × T) = 10000 × 100 / (20000 × 5) = 10%.

6. A sum amounts to ₹10,500 in 4 years at 10% simple interest per annum. What is the sum?

  1. ₹7,498
  2. ₹9,000
  3. ₹7,500
  4. ₹7,499
Answer

C. ₹7,500 Amount = P(1 + 40/100), so P = 10500 ÷ 1.4 = ₹7,500.

7. At what time will a sum double itself at 20% simple interest per annum?

  1. 3 years
  2. 5 years
  3. 7 years
  4. 6 years
Answer

B. 5 years Doubling means SI = P. P × 20 × T / 100 = P, so T = 100/20 = 5 years.

8. Find the simple interest on ₹15,500 at 9% per annum for 4 years.

  1. ₹5,580
  2. ₹5,578
  3. ₹5,581
  4. ₹6,696
Answer

A. ₹5,580 SI = P × R × T / 100 = 15500 × 9 × 4 / 100 = ₹5,580.

9. The simple interest on ₹10,000 for 5 years is ₹2,000. What is the rate of interest?

  1. 5% p.a.
  2. 8% p.a.
  3. 4% p.a.
  4. 6% p.a.
Answer

C. 4% p.a. R = SI × 100 / (P × T) = 2000 × 100 / (10000 × 5) = 4%.

10. A sum amounts to ₹2,300 in 3 years at 5% simple interest per annum. What is the sum?

  1. ₹1,600
  2. ₹2,001
  3. ₹2,000
  4. ₹2,002
Answer

C. ₹2,000 Amount = P(1 + 15/100), so P = 2300 ÷ 1.15 = ₹2,000.

11. At what time will a sum double itself at 8% simple interest per annum?

  1. 13.5 years
  2. 25 years
  3. 12.5 years
  4. 10.5 years
Answer

C. 12.5 years Doubling means SI = P. P × 8 × T / 100 = P, so T = 100/8 = 12.5 years.

12. Find the simple interest on ₹19,000 at 12% per annum for 2 years.

  1. ₹4,558
  2. ₹5,700
  3. ₹5,016
  4. ₹4,560
Answer

D. ₹4,560 SI = P × R × T / 100 = 19000 × 12 × 2 / 100 = ₹4,560.

13. The simple interest on ₹7,000 for 3 years is ₹840. What is the rate of interest?

  1. 5% p.a.
  2. 4% p.a.
  3. 3% p.a.
  4. 8% p.a.
Answer

B. 4% p.a. R = SI × 100 / (P × T) = 840 × 100 / (7000 × 3) = 4%.

14. A sum amounts to ₹23,010 in 3 years at 6% simple interest per annum. What is the sum?

  1. ₹19,500
  2. ₹15,600
  3. ₹19,498
  4. ₹24,375
Answer

A. ₹19,500 Amount = P(1 + 18/100), so P = 23010 ÷ 1.18 = ₹19,500.

15. At what time will a sum double itself at 10% simple interest per annum?

  1. 10 years
  2. 20 years
  3. 8 years
  4. 14 years
Answer

A. 10 years Doubling means SI = P. P × 10 × T / 100 = P, so T = 100/10 = 10 years.

16. Find the simple interest on ₹6,500 at 5% per annum for 4 years.

  1. ₹1,301
  2. ₹1,300
  3. ₹1,430
  4. ₹975
Answer

B. ₹1,300 SI = P × R × T / 100 = 6500 × 5 × 4 / 100 = ₹1,300.

17. The simple interest on ₹10,000 for 3 years is ₹1,200. What is the rate of interest?

  1. 7% p.a.
  2. 3% p.a.
  3. 4% p.a.
  4. 6% p.a.
Answer

C. 4% p.a. R = SI × 100 / (P × T) = 1200 × 100 / (10000 × 3) = 4%.

18. A sum amounts to ₹9,750 in 5 years at 6% simple interest per annum. What is the sum?

  1. ₹7,500
  2. ₹5,625
  3. ₹9,375
  4. ₹7,501
Answer

A. ₹7,500 Amount = P(1 + 30/100), so P = 9750 ÷ 1.3 = ₹7,500.

19. At what time will a sum double itself at 12.5% simple interest per annum?

  1. 6 years
  2. 4 years
  3. 8 years
  4. 10 years
Answer

C. 8 years Doubling means SI = P. P × 12.5 × T / 100 = P, so T = 100/12.5 = 8 years.

20. Find the simple interest on ₹7,500 at 5% per annum for 3 years.

  1. ₹900
  2. ₹1,013
  3. ₹1,125
  4. ₹1,123
Answer

C. ₹1,125 SI = P × R × T / 100 = 7500 × 5 × 3 / 100 = ₹1,125.

21. The simple interest on ₹13,000 for 5 years is ₹3,900. What is the rate of interest?

  1. 8% p.a.
  2. 9% p.a.
  3. 6% p.a.
  4. 7% p.a.
Answer

C. 6% p.a. R = SI × 100 / (P × T) = 3900 × 100 / (13000 × 5) = 6%.

22. A sum amounts to ₹6,600 in 4 years at 8% simple interest per annum. What is the sum?

  1. ₹5,500
  2. ₹5,000
  3. ₹6,000
  4. ₹4,998
Answer

B. ₹5,000 Amount = P(1 + 32/100), so P = 6600 ÷ 1.32 = ₹5,000.

23. Find the simple interest on ₹22,000 at 10% per annum for 5 years.

  1. ₹9,900
  2. ₹10,998
  3. ₹11,000
  4. ₹13,750
Answer

C. ₹11,000 SI = P × R × T / 100 = 22000 × 10 × 5 / 100 = ₹11,000.

24. The simple interest on ₹20,000 for 3 years is ₹6,000. What is the rate of interest?

  1. 10% p.a.
  2. 12% p.a.
  3. 13% p.a.
  4. 20% p.a.
Answer

A. 10% p.a. R = SI × 100 / (P × T) = 6000 × 100 / (20000 × 3) = 10%.

25. A sum amounts to ₹16,520 in 3 years at 6% simple interest per annum. What is the sum?

  1. ₹13,999
  2. ₹14,002
  3. ₹14,000
  4. ₹14,001
Answer

C. ₹14,000 Amount = P(1 + 18/100), so P = 16520 ÷ 1.18 = ₹14,000.

26. Find the simple interest on ₹8,000 at 12% per annum for 3 years.

  1. ₹2,160
  2. ₹2,878
  3. ₹3,456
  4. ₹2,880
Answer

D. ₹2,880 SI = P × R × T / 100 = 8000 × 12 × 3 / 100 = ₹2,880.

27. The simple interest on ₹18,000 for 5 years is ₹9,000. What is the rate of interest?

  1. 9% p.a.
  2. 12% p.a.
  3. 10% p.a.
  4. 13% p.a.
Answer

C. 10% p.a. R = SI × 100 / (P × T) = 9000 × 100 / (18000 × 5) = 10%.

28. A sum amounts to ₹4,760 in 3 years at 12% simple interest per annum. What is the sum?

  1. ₹3,500
  2. ₹3,150
  3. ₹3,498
  4. ₹4,375
Answer

A. ₹3,500 Amount = P(1 + 36/100), so P = 4760 ÷ 1.3599999999999999 = ₹3,500.

29. Find the simple interest on ₹23,000 at 4% per annum for 3 years.

  1. ₹2,760
  2. ₹2,484
  3. ₹3,312
  4. ₹2,208
Answer

A. ₹2,760 SI = P × R × T / 100 = 23000 × 4 × 3 / 100 = ₹2,760.

30. The simple interest on ₹8,000 for 2 years is ₹1,280. What is the rate of interest?

  1. 8% p.a.
  2. 16% p.a.
  3. 11% p.a.
  4. 7% p.a.
Answer

A. 8% p.a. R = SI × 100 / (P × T) = 1280 × 100 / (8000 × 2) = 8%.

31. A sum amounts to ₹8,450 in 5 years at 6% simple interest per annum. What is the sum?

  1. ₹6,501
  2. ₹6,499
  3. ₹6,500
  4. ₹5,200
Answer

C. ₹6,500 Amount = P(1 + 30/100), so P = 8450 ÷ 1.3 = ₹6,500.

32. Find the simple interest on ₹3,500 at 10% per annum for 6 years.

  1. ₹1,575
  2. ₹2,520
  3. ₹2,100
  4. ₹2,101
Answer

C. ₹2,100 SI = P × R × T / 100 = 3500 × 10 × 6 / 100 = ₹2,100.

33. The simple interest on ₹9,000 for 5 years is ₹2,700. What is the rate of interest?

  1. 6% p.a.
  2. 7% p.a.
  3. 8% p.a.
  4. 12% p.a.
Answer

A. 6% p.a. R = SI × 100 / (P × T) = 2700 × 100 / (9000 × 5) = 6%.

34. A sum amounts to ₹4,400 in 2 years at 5% simple interest per annum. What is the sum?

  1. ₹3,998
  2. ₹4,800
  3. ₹4,000
  4. ₹4,001
Answer

C. ₹4,000 Amount = P(1 + 10/100), so P = 4400 ÷ 1.1 = ₹4,000.

35. Find the simple interest on ₹4,500 at 9% per annum for 3 years.

  1. ₹1,337
  2. ₹1,094
  3. ₹1,215
  4. ₹1,458
Answer

C. ₹1,215 SI = P × R × T / 100 = 4500 × 9 × 3 / 100 = ₹1,215.

36. The simple interest on ₹20,000 for 2 years is ₹2,000. What is the rate of interest?

  1. 6% p.a.
  2. 8% p.a.
  3. 7% p.a.
  4. 5% p.a.
Answer

D. 5% p.a. R = SI × 100 / (P × T) = 2000 × 100 / (20000 × 2) = 5%.

37. A sum amounts to ₹27,200 in 5 years at 12% simple interest per annum. What is the sum?

  1. ₹16,998
  2. ₹17,000
  3. ₹17,001
  4. ₹13,600
Answer

B. ₹17,000 Amount = P(1 + 60/100), so P = 27200 ÷ 1.6 = ₹17,000.

38. Find the simple interest on ₹13,000 at 12% per annum for 3 years.

  1. ₹5,148
  2. ₹3,510
  3. ₹4,682
  4. ₹4,680
Answer

D. ₹4,680 SI = P × R × T / 100 = 13000 × 12 × 3 / 100 = ₹4,680.

39. The simple interest on ₹16,000 for 4 years is ₹3,840. What is the rate of interest?

  1. 6% p.a.
  2. 9% p.a.
  3. 8% p.a.
  4. 7% p.a.
Answer

A. 6% p.a. R = SI × 100 / (P × T) = 3840 × 100 / (16000 × 4) = 6%.

40. A sum amounts to ₹2,800 in 2 years at 6% simple interest per annum. What is the sum?

  1. ₹2,000
  2. ₹3,125
  3. ₹2,500
  4. ₹1,875
Answer

C. ₹2,500 Amount = P(1 + 12/100), so P = 2800 ÷ 1.12 = ₹2,500.

41. Find the simple interest on ₹16,500 at 10% per annum for 4 years.

  1. ₹6,599
  2. ₹4,950
  3. ₹7,920
  4. ₹6,600
Answer

D. ₹6,600 SI = P × R × T / 100 = 16500 × 10 × 4 / 100 = ₹6,600.

42. The simple interest on ₹17,000 for 4 years is ₹3,400. What is the rate of interest?

  1. 4% p.a.
  2. 6% p.a.
  3. 7% p.a.
  4. 5% p.a.
Answer

D. 5% p.a. R = SI × 100 / (P × T) = 3400 × 100 / (17000 × 4) = 5%.

43. A sum amounts to ₹14,000 in 4 years at 10% simple interest per annum. What is the sum?

  1. ₹9,999
  2. ₹10,000
  3. ₹9,000
  4. ₹12,000
Answer

B. ₹10,000 Amount = P(1 + 40/100), so P = 14000 ÷ 1.4 = ₹10,000.

44. Find the simple interest on ₹10,500 at 4% per annum for 2 years.

  1. ₹840
  2. ₹924
  3. ₹841
  4. ₹838
Answer

A. ₹840 SI = P × R × T / 100 = 10500 × 4 × 2 / 100 = ₹840.

45. A sum amounts to ₹22,940 in 3 years at 8% simple interest per annum. What is the sum?

  1. ₹18,498
  2. ₹14,800
  3. ₹22,200
  4. ₹18,500
Answer

D. ₹18,500 Amount = P(1 + 24/100), so P = 22940 ÷ 1.24 = ₹18,500.

46. Find the simple interest on ₹10,500 at 9% per annum for 3 years.

  1. ₹3,544
  2. ₹2,835
  3. ₹2,552
  4. ₹3,119
Answer

B. ₹2,835 SI = P × R × T / 100 = 10500 × 9 × 3 / 100 = ₹2,835.

47. A sum amounts to ₹26,000 in 3 years at 10% simple interest per annum. What is the sum?

  1. ₹18,000
  2. ₹16,000
  3. ₹20,002
  4. ₹20,000
Answer

D. ₹20,000 Amount = P(1 + 30/100), so P = 26000 ÷ 1.3 = ₹20,000.

48. Find the simple interest on ₹10,000 at 4% per annum for 2 years.

  1. ₹802
  2. ₹600
  3. ₹880
  4. ₹800
Answer

D. ₹800 SI = P × R × T / 100 = 10000 × 4 × 2 / 100 = ₹800.

49. A sum amounts to ₹6,750 in 5 years at 10% simple interest per annum. What is the sum?

  1. ₹3,375
  2. ₹3,600
  3. ₹5,625
  4. ₹4,500
Answer

D. ₹4,500 Amount = P(1 + 50/100), so P = 6750 ÷ 1.5 = ₹4,500.

50. Find the simple interest on ₹12,000 at 8% per annum for 4 years.

  1. ₹3,840
  2. ₹3,842
  3. ₹3,456
  4. ₹2,880
Answer

A. ₹3,840 SI = P × R × T / 100 = 12000 × 8 × 4 / 100 = ₹3,840.

51. Find the simple interest on ₹1800 at 17% per annum for 12 years.

  1. 3674
  2. 3682
  3. 3665
  4. 3672
Answer

D. 3672 SI = P×R×T/100 = 1800×17×12/100 = ₹3672.

52. Find the simple interest on ₹5900 at 17% per annum for 7 years.

  1. 7031
  2. 7021
  3. 7018
  4. 7016
Answer

B. 7021 SI = P×R×T/100 = 5900×17×7/100 = ₹7021.

53. Find the simple interest on ₹9200 at 18% per annum for 9 years.

  1. 14904
  2. 14899
  3. 14905
  4. 14902
Answer

A. 14904 SI = P×R×T/100 = 9200×18×9/100 = ₹14904.

54. Find the simple interest on ₹11500 at 4% per annum for 7 years.

  1. 3222
  2. 3217
  3. 3220
  4. 3230
Answer

C. 3220 SI = P×R×T/100 = 11500×4×7/100 = ₹3220.

55. Find the simple interest on ₹7100 at 10% per annum for 11 years.

  1. 7805
  2. 7800
  3. 7815
  4. 7810
Answer

D. 7810 SI = P×R×T/100 = 7100×10×11/100 = ₹7810.

56. Find the simple interest on ₹8100 at 6% per annum for 5 years.

  1. 2427
  2. 2423
  3. 2431
  4. 2430
Answer

D. 2430 SI = P×R×T/100 = 8100×6×5/100 = ₹2430.

57. Find the simple interest on ₹1400 at 5% per annum for 6 years.

  1. 425
  2. 415
  3. 420
  4. 421
Answer

C. 420 SI = P×R×T/100 = 1400×5×6/100 = ₹420.

58. Find the simple interest on ₹7200 at 15% per annum for 8 years.

  1. 8640
  2. 8645
  3. 8639
  4. 8635
Answer

A. 8640 SI = P×R×T/100 = 7200×15×8/100 = ₹8640.

59. Find the simple interest on ₹8700 at 5% per annum for 13 years.

  1. 5662
  2. 5655
  3. 5645
  4. 5652
Answer

B. 5655 SI = P×R×T/100 = 8700×5×13/100 = ₹5655.

60. Find the simple interest on ₹5200 at 11% per annum for 2 years.

  1. 1149
  2. 1147
  3. 1144
  4. 1143
Answer

C. 1144 SI = P×R×T/100 = 5200×11×2/100 = ₹1144.

61. Find the simple interest on ₹5500 at 15% per annum for 6 years.

  1. 4960
  2. 4950
  3. 4943
  4. 4945
Answer

B. 4950 SI = P×R×T/100 = 5500×15×6/100 = ₹4950.

62. Find the simple interest on ₹4500 at 2% per annum for 15 years.

  1. 1350
  2. 1340
  3. 1357
  4. 1353
Answer

A. 1350 SI = P×R×T/100 = 4500×2×15/100 = ₹1350.

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